document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32152>Question 32152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 5 times another.  The sum of their reciprocals is 1/5. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18675 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 1st number be x.<BR>\n" );
document.write( "Then 2nd number is 5x.<BR>\n" );
document.write( "Reciprocals are 1/x and 1/(5x)<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "1/x + 1/(5x)= 1/5<BR>\n" );
document.write( "Multiply thru by 5x to get:<BR>\n" );
document.write( "5+1=x<BR>\n" );
document.write( "x=6 (1st number)<BR>\n" );
document.write( "5x=30 (2nd number)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );