document.write( "Question 254425: [Exponential functions]\r
\n" ); document.write( "\n" ); document.write( "A computer valued at $6500 depreciates at the rate of 14.3% per year.\r
\n" ); document.write( "\n" ); document.write( "I need to write a function that models the value of the computer and find the value of the computer after three years.\r
\n" ); document.write( "\n" ); document.write( "At first I wrote y=6500(1.143)^x as the function, but when I checked in the back of the textbook, it said y=6500(0.857)^x. How did they get that number?\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #186734 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
it depreciates at the rate of 14.3% per year.\r
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\n" ); document.write( "\n" ); document.write( "this means that the value drops by 14.3% per year.\r
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\n" ); document.write( "\n" ); document.write( "14.3% / 100% = .143\r
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\n" ); document.write( "\n" ); document.write( "your equation increased the value by 14.3% per year.\r
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\n" ); document.write( "\n" ); document.write( "you added .1453*6500 to 6500 to get:\r
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\n" ); document.write( "\n" ); document.write( "\"6500+%2B+%286500+%2A+.143%29\".\r
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\n" ); document.write( "\n" ); document.write( "when you factor out the 6500, you get:\r
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\n" ); document.write( "\n" ); document.write( "\"6500+%2A+%281+%2B+.143%29\" = \"6500+%2A+1.143\".\r
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\n" ); document.write( "\n" ); document.write( "that does it for one year.\r
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\n" ); document.write( "\n" ); document.write( "for n years, you then raised to the exponent of n to get:\r
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\n" ); document.write( "\n" ); document.write( "\"6500+%2A+1.143%5En\".\r
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\n" ); document.write( "\n" ); document.write( "your equation should have the decreased the value by 14.3% per year.\r
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\n" ); document.write( "\n" ); document.write( "you needed to subtract .143*6500 from 6500 to get:\r
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\n" ); document.write( "\n" ); document.write( "\"6500+-+%286500+%2A+.143%29\".\r
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\n" ); document.write( "\n" ); document.write( "when you factor out the 6500, you get:\r
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\n" ); document.write( "\n" ); document.write( "\"6500+%2A+%281+-+.143%29\" = \"6500+%2A+.857\"\r
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\n" ); document.write( "\n" ); document.write( "that does it for one year.\r
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\n" ); document.write( "\n" ); document.write( "for n years, you then raised to the exponent of n to get:\r
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\n" ); document.write( "\n" ); document.write( "\"6500+%2A+.857%5En\"\r
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\n" ); document.write( "\n" ); document.write( "where you used x, I used n. \r
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\n" ); document.write( "\n" ); document.write( "if you prefer to use x, just replace n with x.\r
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\n" ); document.write( "\n" ); document.write( "graph of \"y+=+6500+%2A+%281.143%29%5Ex\" looks like this.\r
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\n" ); document.write( "\n" ); document.write( "the y values of the graph are in hundreds.\r
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\n" ); document.write( "\n" ); document.write( "6000 = 60
\n" ); document.write( "7000 = 70
\n" ); document.write( "6500 = 65, etc.\r
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\n" ); document.write( "\n" ); document.write( "the only x values you are interested are when x is positive.\r
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\n" ); document.write( "\n" ); document.write( "those values are to the right of the y-axis which is the vertical line when x = 0.\r
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\n" ); document.write( "\n" ); document.write( "\"graph+%28400%2C400%2C-1%2C10%2C-20%2C200%2C65%2A%281.143%29%5Ex%29\"\r
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\n" ); document.write( "\n" ); document.write( "you can see that as x increases, the value of y increases.\r
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\n" ); document.write( "\n" ); document.write( "graph of \"y+=+6500+%2A+%28.857%29%5Ex\" looks like this.\r
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\n" ); document.write( "\n" ); document.write( "\"graph+%28400%2C400%2C-1%2C10%2C-20%2C200%2C65%2A%28.857%29%5Ex%29\"\r
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\n" ); document.write( "\n" ); document.write( "you can see that as x increases, the value of y decreases.\r
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