document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32114>Question 32114</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (Sir i am in confussion with this question & i need an answer fastly as possible)                                                                                      Q. A person travels 600 km to his home , partly by train and partly by car . He takes 8 hours if he travels 120km by train abd the rest by car . He takes 20 minutes longer if he travels 200 km by train and the rest by car . Find the speed of the train and the car ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18673 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> On the 1st 600km trip:<BR>\n" );
document.write( "Train Data: distance=120km, time=x hrs. rate=120/x<BR>\n" );
document.write( "Car Data:   distance=480km, time=8-x hrs. rate=480/(8-x)\r<BR>\n" );
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document.write( "On the 2nd 600km trip:<BR>\n" );
document.write( "Train Data: distance=200km, time=y hrs, rate=200/y<BR>\n" );
document.write( "Car Data: distance=400km, time=25/3-y, rate= 400/[(25/3)-y] <BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( " Train Rate on 1st trip = Train rate on 2nd trip<BR>\n" );
document.write( "     120/x=200/y<BR>\n" );
document.write( "     Then x=(3/5)y\r<BR>\n" );
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document.write( " Car Rate on 1st trip = Car Rate on 2nd trip<BR>\n" );
document.write( "   480/(8-x)=400/(25/3)-y]\r<BR>\n" );
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document.write( "Substitute x=(3/5)y into this second equation<BR>\n" );
document.write( "and reduce the numerators, to get:<BR>\n" );
document.write( " 6/(8-x)=5/[(25/3)-y]<BR>\n" );
document.write( " 6[25/3 - y] = 5[8-3y/5)]<BR>\n" );
document.write( " 50-6y=40-3y<BR>\n" );
document.write( "10=3y<BR>\n" );
document.write( "y=(10/3) hrs (time for car on 2nd 200km trip)<BR>\n" );
document.write( "Then x=(3/5)(10/3)= 2 hrs (time for train on 1st 600km trip)\r<BR>\n" );
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document.write( "Speed of train = 120/x=120/2= 60km/hr<BR>\n" );
document.write( "Speed of car = 480/(8-x)= 480/(8-2)=80km/hr<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( "  <BR>\n" );
document.write( "  </SPAN>\n" );
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