document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31819>Question 31819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation for the hyperbola with vertices (2,0) and (-2,0) and asymptote y=1/2x\r<BR>\n" );
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document.write( "(A) 4x^2-y^2=4\r<BR>\n" );
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document.write( "(B) x^2-4y^2=4\r<BR>\n" );
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document.write( "(C) x^2-y^2=4\r<BR>\n" );
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document.write( "(D) x^2+4y^2=4\r<BR>\n" );
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document.write( "Thank you very much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18668 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b/a=1/2 (from asymptote)<BR>\n" );
document.write( "Vertices are at (2,0) and (-2,0); a=2; <BR>\n" );
document.write( "b/a=2 => b=1<BR>\n" );
document.write( "=> center is at (0,0) and transverse axis is x-axis<BR>\n" );
document.write( "So, standard equation is:<BR>\n" );
document.write( "x^2/a^2 - y^2/b^2 = 1<BR>\n" );
document.write( "Required equation is<BR>\n" );
document.write( "x^2/4 - y^2/1 = 1<BR>\n" );
document.write( "=>x^2-4y^2=4<BR>\n" );
document.write( "Correct option is B<BR>\n" );
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