document.write( "Question 254318: What is the value of k if the line 2x + 3y = 3 is perpendicular to the line 2x + ky + 1 = 0? \n" ); document.write( "
Algebra.Com's Answer #186672 by vleith(2983)\"\" \"About 
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for two lines to be perpendicular, their slopes have to have a product of -1\r
\n" ); document.write( "\n" ); document.write( "Find the slope of the first line
\n" ); document.write( "\"2x+%2B+3y++=++3+\"
\n" ); document.write( "\"3y+=+-2x+%2B+3\"
\n" ); document.write( "\"y+=+-%282%2F3%29x+%2B+1\"
\n" ); document.write( "So the slope is \"-2%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Find the slope of the second line
\n" ); document.write( "\"2x+%2B+ky+%2B+1++=++0\"
\n" ); document.write( "\"ky+=+-2x+-+1\"
\n" ); document.write( "\"y+=+-%282%2Fk%29x+-1%2Fk\"
\n" ); document.write( "So the slope of the second line is \"-2%2Fk\"\r
\n" ); document.write( "\n" ); document.write( "Set the product of the two slopes equal to -1
\n" ); document.write( "\"%28-2%2F3%29+%2A+%28-2%2Fk%29+=+-1\"
\n" ); document.write( "\"4%2F3k+=+-1\"
\n" ); document.write( "\"k+=+-4%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Plot the graphs and verify
\n" ); document.write( "\"graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C+-2x%2F3+%2B1+%2C+3x%2F2+%2B+3%2F4%29\"
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