document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32104>Question 32104</A>: <I><SPAN STYLE=\"word-break: break-all;\">  1. A number consists of two digits whose sum is 10 . If 72 be subtracted from the number , the digits are reversed . find the number ?                                         2. Two kg of sugar and 1/2 kg of tea cost Rs.32 and 3 kg of sugar and 1 kg of tea cost Rs.59. Find the cost of 1 kg of tea 1kg of sugar ?       </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18666 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be 10x+y<BR>\n" );
document.write( "x+y=10;<BR>\n" );
document.write( "10x+y-72=10y+x<BR>\n" );
document.write( "=>9x-9y=72<BR>\n" );
document.write( "=>x-y=8;<BR>\n" );
document.write( "We need to solve for x and y from the following equations:<BR>\n" );
document.write( "x+y=10<BR>\n" );
document.write( "x-y=8<BR>\n" );
document.write( "Adding above:<BR>\n" );
document.write( "2x=18<BR>\n" );
document.write( "=>x=9<BR>\n" );
document.write( "y=10-x=1<BR>\n" );
document.write( "So, the original number is 91 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );