document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254169>Question 254169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2(a-8)+7=5(a+2)-3a-19 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #186626 by </B><A HREF=/tutors/aboutme.mpl?userid=JimboP1977><B>JimboP1977(311)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JimboP1977><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JimboP1977><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=186626\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First multiply 2 by (a-8) to give 2a-16. Do the same for 5 and (a+10).\r<BR>\n" );
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document.write( "This gives 2a-16+7=5a+10-3a-19\r<BR>\n" );
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document.write( "Take 3a away from 5a to give 2a and take 19 away from 10 to give -9. Also add 7 to -16 to give -9.\r<BR>\n" );
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document.write( " We know this must be true, for all real values of a! </SPAN>\n" );
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