document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254195>Question 254195</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parallel tracks.  Train A is traveling at 40 MPH and train B traveling at 60 MPH.  train A passes a station at 9:20 PM.  If train B passes the same station at 9:34 PM at what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #186618 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=186618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=40t for train A.<BR>\n" );
document.write( "d=60(t-14/60) train B.<BR>\n" );
document.write( "40t=60(t-14/60)<BR>\n" );
document.write( "40t=60t-14<BR>\n" );
document.write( "40t-60t=-14<BR>\n" );
document.write( "-20t=-14<BR>\n" );
document.write( "t=-14/-20=7/10=.7 hours.<BR>\n" );
document.write( ".7*60=42 minutes.<BR>\n" );
document.write( "9:20+:42=10:02 is the time they will meet.<BR>\n" );
document.write( " </SPAN>\n" );
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