document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=254256>Question 254256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one angle is twice the size of a second angle.<BR>\n" );
document.write( "The sum of the angles is 150 degrees. How many <BR>\n" );
document.write( "degrees are in each angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #186588 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=186588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X = first angle and Y = second angle.<BR>\n" );
document.write( "X = 2Y<BR>\n" );
document.write( "X + Y = 150<BR>\n" );
document.write( "By substitution, we get<BR>\n" );
document.write( "2Y + Y = 150<BR>\n" );
document.write( "and solving for Y, we get<BR>\n" );
document.write( " Y = 50<BR>\n" );
document.write( "This means X = 100. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );