document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4189>Question 4189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HOW IS THIS DONE?\r<BR>\n" );
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document.write( "WHAT IS THE SLOPE OF A LINE THAT IS PERPENDICULAR TO THE LINE PASSING THROUGH THE POINTS (8,3) AND (10,6)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1865 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1865\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first, find the gradient of the line that passes through the 2 points --> look at my lessons on this topic on this site. They are easy to follow and explain it well.\r<BR>\n" );
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document.write( "Once you have that, you need to know that 2 lines that are perpendicular, will have gradients m1 and m2 such that m1*m2 = -1.\r<BR>\n" );
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document.write( "So, if your gradient is 3, then the perpendicular line has a gradient of -1/3.\r<BR>\n" );
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document.write( "Jon<BR>\n" );
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