document.write( "Question 254096: A pentagon is formed by a rectangle and an equilateral triangle (external to it)with the side (of the triangle) in common with a dimension of the rectangle. Knowing that one dimension of the rectangle measures 4.2 cm and that the diagonal is 7 cm, determine the perimeter and the area of the pentagon.\r
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document.write( "I just can't figure out the figure. I tried using a square, but it doesn't seem to work right... And it can't be a rectangle because then all the sides of the pentagon would not be egual. I would really appreciate all the help I can get! Thank you! \n" );
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Algebra.Com's Answer #186491 by edjones(8007)![]() ![]() You can put this solution on YOUR website! This is not a regular pentagon. The sides are not equal. \n" ); document.write( "For the sides of the rectangle: \n" ); document.write( "a^+b^2=c^2 \n" ); document.write( "a^2+4.2^2=7^2 \n" ); document.write( "a^2+17.64=49 \n" ); document.write( "a^2=31.36 \n" ); document.write( "a=5.6 \n" ); document.write( "So the rectangle's sides are 5.6 and 4.2 \n" ); document.write( "We can make the sides of the triangle either number; I will use 4.2; you can use 5.6 if you wish. \n" ); document.write( "A=s^2sqrt(3)/4 for an equilateral triangle. \n" ); document.write( "=17.64sqrt(3)/4 \n" ); document.write( "=4.41sqrt(3) \n" ); document.write( "5.6*4.2*4.41sqrt(3)=179.7 sq cm Area of pentagon \n" ); document.write( "5.6*2+4.2*3=23.8 cm Perimeter of pentagon. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |