document.write( "Question 254096: A pentagon is formed by a rectangle and an equilateral triangle (external to it)with the side (of the triangle) in common with a dimension of the rectangle. Knowing that one dimension of the rectangle measures 4.2 cm and that the diagonal is 7 cm, determine the perimeter and the area of the pentagon.\r
\n" ); document.write( "\n" ); document.write( "I just can't figure out the figure. I tried using a square, but it doesn't seem to work right... And it can't be a rectangle because then all the sides of the pentagon would not be egual. I would really appreciate all the help I can get! Thank you!
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Algebra.Com's Answer #186491 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
This is not a regular pentagon. The sides are not equal.
\n" ); document.write( "For the sides of the rectangle:
\n" ); document.write( "a^+b^2=c^2
\n" ); document.write( "a^2+4.2^2=7^2
\n" ); document.write( "a^2+17.64=49
\n" ); document.write( "a^2=31.36
\n" ); document.write( "a=5.6
\n" ); document.write( "So the rectangle's sides are 5.6 and 4.2
\n" ); document.write( "We can make the sides of the triangle either number; I will use 4.2; you can use 5.6 if you wish.
\n" ); document.write( "A=s^2sqrt(3)/4 for an equilateral triangle.
\n" ); document.write( "=17.64sqrt(3)/4
\n" ); document.write( "=4.41sqrt(3)
\n" ); document.write( "5.6*4.2*4.41sqrt(3)=179.7 sq cm Area of pentagon
\n" ); document.write( "5.6*2+4.2*3=23.8 cm Perimeter of pentagon.
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