document.write( "Question 254095: Roman mixes 12 liters of 8% acid solution with a 20% acid solution, which results in a 16% acid solution. Find the number of liters of 20% acid solution in the new mixture. \n" ); document.write( "
Algebra.Com's Answer #186471 by ptaylor(2198)\"\" \"About 
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Let x=the number of liters of the 20% solution in the new mixture
\n" ); document.write( "Now we know that the amount of pure acid in the 8% solution (0.08*12) plus the amount of pure acid in the 20% solution (0.20x) has to equal the amount of pure acid in the new mixture (0.16(12+x)). So our equation to solve is:
\n" ); document.write( "0.08*12+0.20x=0.16(12+x) get rid of parens and simplify
\n" ); document.write( "0.96+0.20x=1.92+0.16x subtract 0.16x and also 0.96 from each side
\n" ); document.write( "0.96-0.96+0.20x-0.16x=1.92-0.96+0.16x-0.16x collect like terms
\n" ); document.write( "0.04x=0.96 divide each side by 0.04
\n" ); document.write( "x=24 liters----------------------amount of 20% solution needed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.08*12+0.20*24=0.16(12+24)
\n" ); document.write( "0.96+4.8=5.76
\n" ); document.write( "5.76=5.76\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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