document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32136>Question 32136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the denominator of a fraction is added to its numerator and the numerator is subtracted from its denominator , the fraction becomes 11/3 . If the numerator exceeds the denominator by 3 , find the fraction ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18644 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18644\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> N=D+3 & (N+D)/(D-N)=11/3 OR SUBSTITUTING D+3 FOR N WE GET \r<BR>\n" );
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document.write( "((D+3)+D)/(D-(D+3)=11/3 OR (2D+3)/-3=11/3 OR CROSS MULTIPLYING WE GET 6D+9=-33<BR>\n" );
document.write( "OR 6D=-42 OR D=-7 THEREFORE N=-7+3 OR N=-4\r<BR>\n" );
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document.write( "PROOF ((-4+(-7)))/(-7)-(-4)=11/3 OR -11/(-7+4)=11/3 OR -11/-3=11/3 OR 11/3=11/3 </SPAN>\n" );
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