document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32128>Question 32128</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man rowing at the rate of 5 km an hour in still water takes thrice as much time in going 40 km up the river as in going 40 km down . Find the rate at which the river flows ? ( Sir pls give me an quick answer ) (thanks ) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18642 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18642\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> EQUATIONS ARE UPSTREAM (5-C) C IS THE CURRENT AND DOWN STREAM (5+C) AND IT TAKES TWICE AS LONG TO GO UP STREAM THAN DOWN STREAM THEREFORE \r<BR>\n" );
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document.write( "2(5-C)=(5+C) OR 10-2C=5+C OR -3C=-5 OR C=5/3KM AN HOUR \r<BR>\n" );
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document.write( "PROOF 2(5-5/3)=5+5/3 OR 10-10/3=5+5/3 OR 10-3 1/3=5+5/3 OR 6 2/3 =6 2/3<BR>\n" );
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