document.write( "Question 254081: Car A and car B both travel 560 miles. Car A drove at an average speed of 10 miles per hour faster than car B and made the trip in one hour less time. Find the average speeds of both cars. \n" ); document.write( "
Algebra.Com's Answer #186390 by palanisamy(496)\"\" \"About 
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Let the speed of car A be x.
\n" ); document.write( "Then,the speed of car B is x-10.
\n" ); document.write( "Distance travelled = 560 mile.
\n" ); document.write( "Time taken by car A = 560/x
\n" ); document.write( "Time taken by car B = 560/(x-10)
\n" ); document.write( "Given
\n" ); document.write( " 560/x -10 = 560/(x-10)
\n" ); document.write( " (5600-10x)/10x = 560/(x-10)
\n" ); document.write( " (5600-10x)(x-10) = 5600x
\n" ); document.write( " 5600x-56000-10x^2+100x = 5600x
\n" ); document.write( " -10x^2+100x-56000 = 0
\n" ); document.write( " x^2-10x+5600 = 0
\n" ); document.write( " (x-80)(x+70) = 0
\n" ); document.write( " x = 80 or -70
\n" ); document.write( " x cannot be negative.
\n" ); document.write( " So, x = 80
\n" ); document.write( "Therefore,the speed of car A is 80 miles/h
\n" ); document.write( "and,the speed of car B is x-10 = 80-10 = 70 miles/h
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