document.write( "Question 254073: Train A travels 10 mi/h slower than train B. Train A travels 400 miles in the same time that train B travels 500 miles. Find the speed of each train.\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance! :)
\n" ); document.write( "

Algebra.Com's Answer #186377 by palanisamy(496)\"\" \"About 
You can put this solution on YOUR website!
Let the speed of the train A be x
\n" ); document.write( "Then,the speed of the train B is x+10
\n" ); document.write( "Given,Train A travels 400 miles in the same time that train B travels 500 miles
\n" ); document.write( " 400/x = 500/(x+10)
\n" ); document.write( " 400(x+10) = 500x
\n" ); document.write( " 4(x+10) = 5x
\n" ); document.write( " 4x+40 = 5x
\n" ); document.write( " 40 = 5x-4x
\n" ); document.write( " 40 = x
\n" ); document.write( "So,the speed of the train A is 40 miles per hour
\n" ); document.write( "the speed of the train Bis x+10 = 50 miles per hour
\n" ); document.write( "
\n" ); document.write( "
\n" );