document.write( "Question 32118: In a flight of 2800 km , an aircraft was slowed down due to bad weather . Its average speed for the trip was reduced by 100km per hour and time icreased by 30 minutes . Find the original duration of flight ? \n" ); document.write( "
Algebra.Com's Answer #18633 by Paul(988)\"\" \"About 
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Let the average speed be x
\n" ); document.write( "When it is decreased it will be: x-100
\n" ); document.write( "and time increased by 30 minutes or 0.5 hours:
\n" ); document.write( "TOtal distance of flying wil respect to speed and time = 2800
\n" ); document.write( "Equation:
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Cross multiply
\n" ); document.write( "2800[(x)-(x-100)]=0.5[(x)(x-100)]
\n" ); document.write( "\"2800%28100%29=0.5%28x%5E2-100x%29\"
\n" ); document.write( "\"0.5x%5E2-50x-280000\"
\n" ); document.write( "Multiply the eqauiton by 2 to remove the decimal:
\n" ); document.write( "\"x%5E2-100x-560000=0\"
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\n" ); document.write( "In quadratic equation: a=1, b=-100, c=-560000
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\n" ); document.write( "Simplfy
\n" ); document.write( "x=-700 or x=800
\n" ); document.write( "Hence, the average speed was 800km/h.
\n" ); document.write( "Paul.
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