document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253939>Question 253939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a mother who is 40 years old has a 10 year old daughter. In how many years will the mother be three times as old as the daughter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #186305 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=186305\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a mother who is 40 years old has a 10 year old daughter. In how many years will the mother be three times as old as the daughter?<BR>\n" );
document.write( "You may edit the question. Maybe convert formulae \r<BR>\n" );
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document.write( "Let x be the number of years when the mother's age  will be 3 times the daughters.\r<BR>\n" );
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document.write( "Then:\r<BR>\n" );
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document.write( "40 + x = (10 + x) * 3\r<BR>\n" );
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document.write( "40 + x = 30 + 3x  <BR>\n" );
document.write( "2x = 10<BR>\n" );
document.write( "X = 5 </SPAN>\n" );
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