document.write( "Question 253929: Address book. The perimeter of the cover of an address book is 14 inches, and the diagonal measures 5 inches. What are the length and width of the cover? \n" ); document.write( "
Algebra.Com's Answer #186289 by stanbon(75887)\"\" \"About 
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Address book. The perimeter of the cover of an address book is 14 inches, and the diagonal measures 5 inches. What are the length and width of the cover?
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\n" ); document.write( "Perimeter = 2(L + W) = 14\"
\n" ); document.write( "L+W = 7\"
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\n" ); document.write( "Pythagorean
\n" ); document.write( "L^2 + W^2 = 5^2
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\n" ); document.write( "L = 7-W
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\n" ); document.write( "Substitute for \"L\":
\n" ); document.write( "(7-W)+W^2 = 25
\n" ); document.write( "49 - 14W + 2W^2 = 25
\n" ); document.write( "2W^2 - 14W + 24 = 0
\n" ); document.write( "W^2 - 7W + 12 = 0
\n" ); document.write( "(W-3)(W-4) = 0
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\n" ); document.write( "If W = 3, L = 7-W = 4
\n" ); document.write( "If W = 4, L = 7-W = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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