document.write( "Question 253925: please help me: \r
\n" ); document.write( "\n" ); document.write( "\"2y%2Fy-1+=+5%2Fy+%2B+10-8y%2Fy%5E2-y\"
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Algebra.Com's Answer #186271 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2y/(y-1) = 5/y + 10-8y/(y^2-y)
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\n" ); document.write( "Multiply thru by y(y-1) to get:
\n" ); document.write( "2y(y) = 5(y-1) + 10y(y-1) - 8y
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\n" ); document.write( "2y^2 = 5y-1 + 10y^2 - 10y - 8y
\n" ); document.write( "2y^2 = -13y + 10y^2
\n" ); document.write( "8y^2 - 13y = 0
\n" ); document.write( "y(8y - 13) = 0
\n" ); document.write( "y = 0 or y = 13/8
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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