document.write( "Question 253874: beryllium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 240 g of beryllium-11 to decompose into 7.5g of beryllium-11? \r
\n" ); document.write( "\n" ); document.write( "based on the forumula provided in the text book C(t)=C(0)2e^-t/h\r
\n" ); document.write( "\n" ); document.write( "where C(0) = 240, C(t)=7.5 ,h=13.8\r
\n" ); document.write( "\n" ); document.write( "7.5/240=2e^-t/13.8\r
\n" ); document.write( "\n" ); document.write( "this was a s far as i got
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Algebra.Com's Answer #186255 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your equation to work with is:\r
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\n" ); document.write( "\n" ); document.write( "\"C%5Bt%5D=C%5B0%5D%2A2%2Ae%5E%28-t%2Fh%29\"\r
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\n" ); document.write( "\n" ); document.write( "The exponent in the equation is \"-t%2Fh\".\r
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\n" ); document.write( "\n" ); document.write( "\"C%5B0%5D+=+240\"
\n" ); document.write( "\"C%5Bt%5D+=+7.5\"
\n" ); document.write( "\"h+=+13.8\"\r
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\n" ); document.write( "\n" ); document.write( "substituting in that equation, you get:\r
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\n" ); document.write( "\n" ); document.write( "\"7.5+=+240+%2A+2+%2A+e%5E%28-t%2F13.8%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the exponent in the equation is \"-t%2F13.8%29\"\r
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\n" ); document.write( "\n" ); document.write( "you want to isolate the exponential term on the right hand side of the equation so you need to divide both sides of the equation by 240 * 2 to get:\r
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\n" ); document.write( "\n" ); document.write( "\"7.5%2F%282%2A240%29+=+e%5E%28-t%2F13.8%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the exponent in the equation is \"-t%2F13.8%29\"\r
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\n" ); document.write( "\n" ); document.write( "take the log of both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "\"log%287.5%2F%282%2A240%29%29+=+log%28e%5E%28-t%2F13.8%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "since log(b^c) = c*log(b), your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"log%287.5%2F%282%2A240%29%29+=+%28-t%2F13.8%29+%2A+log%28e%29\"\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by 13.8 to get:\r
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\n" ); document.write( "\n" ); document.write( "\"13.8%2Alog%287.5%2F%282%2A240%29%29+=+-t%2Alog%28e%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by -log(e) to get:\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%2813.8%2Alog%287.5%2F%282%2A240%29%29%29%2F%28-log%28e%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "solve for t to get:\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+-24.92528364%2F-.434294482+=+57.39258655\" seconds.\r
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\n" ); document.write( "\n" ); document.write( "substitute in original equation to see if this value for t is good.\r
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\n" ); document.write( "\n" ); document.write( "original equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"C%5Bt%5D=C%5B0%5D%2A2%2Ae%5E%28-t%2Fh%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "exponent in the equation is \"-t%2Fh\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"C%5B0%5D+=+240\"
\n" ); document.write( "\"C%5Bt%5D+=+7.5\"
\n" ); document.write( "\"h+=+13.8\"
\n" ); document.write( "t = 57.39258655\r
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\n" ); document.write( "\n" ); document.write( "equation becomes:\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"7.5=240%2A2%2Ae%5E%28-57.39258655%2F13.8%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "exponent in the equation is \"%28-57.39258655%2F13.8%29\"\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "\"7.5=480%2Ae%5E%28-4.158883083%29\"\r
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\n" ); document.write( "\n" ); document.write( "simplify further to get:\r
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\n" ); document.write( "\n" ); document.write( "\"7.5+=+7.5\"\r
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\n" ); document.write( "\n" ); document.write( "since the equation is true, the value for t is good.\r
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\n" ); document.write( "\n" ); document.write( "t = 57.39258655 seconds
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