document.write( "Question 253874: beryllium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 240 g of beryllium-11 to decompose into 7.5g of beryllium-11? \r
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document.write( "based on the forumula provided in the text book C(t)=C(0)2e^-t/h\r
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document.write( "where C(0) = 240, C(t)=7.5 ,h=13.8\r
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document.write( "7.5/240=2e^-t/13.8\r
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document.write( "this was a s far as i got \n" );
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Algebra.Com's Answer #186255 by Theo(13342)![]() ![]() You can put this solution on YOUR website! your equation to work with is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The exponent in the equation is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting in that equation, you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the exponent in the equation is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you want to isolate the exponential term on the right hand side of the equation so you need to divide both sides of the equation by 240 * 2 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the exponent in the equation is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take the log of both sides of this equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since log(b^c) = c*log(b), your equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of this equation by 13.8 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by -log(e) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for t to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substitute in original equation to see if this value for t is good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "original equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "exponent in the equation is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "t = 57.39258655\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "equation becomes:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "exponent in the equation is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify further to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the equation is true, the value for t is good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = 57.39258655 seconds \n" ); document.write( " \n" ); document.write( " |