document.write( "Question 32084: Venugopalramana has kindly calculated and ploted the data from y=3cos(2t+ 40 degrees),0 < t < 360 degrees. But I do not know how the data was calculated and how he plotted the data. Could Venugopalramana or another tutor please explain the steps to calculating the data. Thankkyou \n" ); document.write( "
Algebra.Com's Answer #18625 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! sketch y=3cos(2t+ 40 degrees),0 < t < 360 degrees \n" ); document.write( "CALCULATE THE DATA AS SHOWN BELOW AND PLOT THEM ON A GRAPH.IT WILL \n" ); document.write( "LOOK AS GIVEN BELOW. \n" ); document.write( "T-DEG. T-RADIANS y=3cos(2t+ 40 degrees) \n" ); document.write( "0 0.00 2.30........OK I WILL SHOW ONE EXAMPLE.LET US DO FOR T=30 DEGREES \n" ); document.write( "WE CAN CALCULATE WITH DEGREES IF YOU HAVE CALCULATOR WITH DEGREE \n" ); document.write( "MEASURE.....FIND 2T+40=2*30+40=60+40=100...NOW FIND COS(100) DEGREES IN \n" ); document.write( "CALCULATOR..YOU WILL GET IT AS -0.1733....MULTIPLY WITH 3 TO GET \n" ); document.write( "-0.52...CONTINUE THIS WAY FOR DIFFERENT VALUES OF T STARTING FROM 0 \n" ); document.write( "DEGREES AND GOING IN STEPS OF 30 OR 60 DEGREES AS YOU LIKE. \n" ); document.write( "AFTER TABULATING AS SHOWN HERE TAKE A SUITABLE SCALE FOR X AND Y AXIS \n" ); document.write( "AND PLOT THEM FOR T=0 TO 360 DEGREES AS DESIRED....VENUGOPAL \n" ); document.write( "30 0.52 -0.52 \n" ); document.write( "60 1.05 -2.82 \n" ); document.write( "90 1.57 -2.30 \n" ); document.write( "120 2.09 0.52 \n" ); document.write( "150 2.62 2.82 \n" ); document.write( "180 3.14 2.30 \n" ); document.write( "210 3.67 -0.52 \n" ); document.write( "240 4.19 -2.82 \n" ); document.write( "270 4.71 -2.30 \n" ); document.write( "300 5.24 0.52 \n" ); document.write( "330 5.76 2.82 \n" ); document.write( "360 6.28 2.30 \n" ); document.write( " |