document.write( "Question 253865: What are the extraneous solutions and the steps for:\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28x-5%29-sqrt%28x%29=-2\"
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Algebra.Com's Answer #186204 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%28x-5%29-sqrt%28x%29=-2\"
\n" ); document.write( "Square both sides:
\n" ); document.write( "\"%28x-5%29+%2B+x+-+2sqrt%28x%5E2-5x%29+=+4\"
\n" ); document.write( "\"2x-9+=+2sqrt%28x%5E2-5x%29\"
\n" ); document.write( "Square again
\n" ); document.write( "\"4x%5E2+-+36x+%2B+81+=+4x%5E2-20x\"
\n" ); document.write( "\"-+16x+%2B81+=+0\"
\n" ); document.write( "16x = 81
\n" ); document.write( "x = 81/16
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\n" ); document.write( "There are no extraneous solutions.\r
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