document.write( "Question 253836: how do i use the discriminant to determine how many real number solutions the quadratic equation -4j^2+3j-28=0 has? \n" ); document.write( "

Algebra.Com's Answer #186186 by JimboP1977(311) $\"\"$ $\"About$

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$\"b%5E2-4ac\"$ is the discriminant.
\n" ); document.write( " $\"b%5E2-4ac+%3E+0%29\"$ 2 real solutions
\n" ); document.write( " $\"b%5E2-4ac+=+0%29\"$ 1 real solution
\n" ); document.write( " $\"b%5E2-4ac+%3C+0%29\"$ no real solutions\r
\n" ); document.write( "\n" ); document.write( "So in the case of $\"-4j%5E2%2B3j-28=0\"$ the discriminant is $\"9-%284%2A-4%2A-28%29\"$ which is $\"9-%28448%29=+-439\"$ so no real solutions.\r
\n" ); document.write( "\n" ); document.write( "The graph of $\"-4j%5E2%2B3j-28=0\"$ demonstrates this $\"+graph%28+300%2C+200%2C+-50%2C+50%2C+-1000%2C+50%2C+-4x%5E2%2B3x-28%29+\"$ \r
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