document.write( "Question 253809: How do you solve:\r
\n" ); document.write( "\n" ); document.write( "c-5d=2 2c+d=4
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Algebra.Com's Answer #186131 by richwmiller(17219)\"\" \"About 
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\n" ); document.write( "c-5d=2
\n" ); document.write( "2c+d=4
\n" ); document.write( "double the first
\n" ); document.write( "2c-10d=4
\n" ); document.write( "2c+d=4
\n" ); document.write( "As you can see we have 2c in the first and 2c in the second
\n" ); document.write( "and after subtracting 10d we get 4
\n" ); document.write( "but we also get 4 after adding d
\n" ); document.write( "which means that d must equal -10d
\n" ); document.write( "d=-10d
\n" ); document.write( "which would lead to d being 0 or 1=-10\r
\n" ); document.write( "\n" ); document.write( "so d=0
\n" ); document.write( "therefore c=2
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