document.write( "Question 32085This question is from textbook 9781592009428
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document.write( ": Goodevening.I would like to beg you, please help me in this problems
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document.write( " 1)The total interest earned on a sum of money invested for one year was $183. If the $500 more was invested at 1o% simple interest than was invested at 9% simple interest, how much was invested at each rate?\r
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document.write( " 2) geometry problem
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document.write( " In a 30,60 right triangle, if the opposite side of right angle is 6 units, find the area of triangle.
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document.write( " your poor studnent Emmamodi \n" );
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Algebra.Com's Answer #18613 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Let amount invested at 9% be \"x\" \n" ); document.write( "Then amount invested at 10% must be \"x+500\" \n" ); document.write( "Interest on the 9% investment is 0.09x \n" ); document.write( "Interest on the 10% investment is .10(x+500)=0.10x+50 \n" ); document.write( "EQUTION: \n" ); document.write( "Interest + Interest = $183 \n" ); document.write( "0.09x + 0.10x+50 = 183 \n" ); document.write( "9x + 10x + 5000 = 18300 \n" ); document.write( "19x= 13300 \n" ); document.write( "x=$700 (amount invested at 9%) \n" ); document.write( "x+500= $1200 (amount invested at 10%) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |