document.write( "Question 253793: a number is called \" even - odd \" if it is halfway between an even integer and an odd integer. if x is an even-odd number , which of the following must be true ?\r
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document.write( "I. 2x is an integer
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document.write( "II 2x is even-odd
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document.write( "III x is halfway between two even integers\r
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document.write( "A) I only (B) II only (C) I and II only
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document.write( "(D) II and III only (E) I, II, and III
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Algebra.Com's Answer #186113 by Theo(13342)![]() ![]() You can put this solution on YOUR website! pick any odd number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "start with 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take a number greater than it that is even. \n" ); document.write( "take a number less than it that is also even.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take 18 and -18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "these form the odd-even pairs we will work with.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "number halfway between 3 and 18 is 15/2 = 7.5 \n" ); document.write( "number halfway between 3 and -18 is 21/2 = 10.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "neither of these number is an integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "an even-odd number is therefore not an integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 times the number, however, will be an integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 * 7.5 = 15 \n" ); document.write( "2 * 10.5 = 21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "statement 1 is true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 times the number is not even-odd.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "can't be, because 2 times the number is an integer and even-odd number is not an integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "statement 2 is false.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "statement 3 says even-odd integer is halfway between 2 even integers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "can't be because an odd integer is halfway between 2 even integers and the even-odd integers is halfway between one of the even integers and the odd integers so it can't be halfway between the 2 even integers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take the case of 3 and 18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "even-odd integer is halfway between them and is equal to 15/2 = 7.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "closest even integer higher is 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "closest even integer lower is 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7 is halfway between 6 and 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7.5 is therefore not.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a number between 2 even integers will always be an integer which is not an odd-even integer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "statement 3 is false.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your answer should be selection A which is statement 1 is true only.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |