document.write( "Question 253780: If 6 divided by 1 less than a number gives the same result as 15 divided by twice the same number, find the number. \n" ); document.write( "
Algebra.Com's Answer #186093 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
let x = the number\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"6%2F%28x-1%29+=+15%2F2x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "multiply both sides of equation by \"%28x-1%29%2A%282x%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "result is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"6%2A2x+=+15%2A%28x-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "simplify to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"12%2Ax+=+15%2Ax+-+15\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "subtract 12*x from both sides of the equation and add 15 to both sides of the equation to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%2Ax+=+15\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 3 to get 5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );