document.write( "Question 253677: I need help with a very difficult math assignment i have recieved my math teachers makes it way more complicated then it has to be.\r
\n" ); document.write( "\n" ); document.write( "1.) if sin x= (12/13), cos y=(3/5) and x and y are acute angles, the value of cos(x-y) is
\n" ); document.write( "a.(21/65) b.(63-65) c. -(14/65) d. -(33/65)\r
\n" ); document.write( "\n" ); document.write( "2.) if the tangent of an angle is negative and its secant is positive, in which quadrant does the angle terminate
\n" ); document.write( "1,2,3 or 4 i thought it was the second quadrant but i dont understand the term terminate i wasnt sure if that ment the opposite of what it was.\r
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Algebra.Com's Answer #186034 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1.) if sin x= (12/13), cos y=(3/5) and x and y are acute angles, the value of cos(x-y) is
\n" ); document.write( "a.(21/65) b.(63/65) c. -(14/65) d. -(33/65)
\n" ); document.write( "---
\n" ); document.write( "cos(x-y) = cos(x)cos(y)+sin(x)sin(y)
\n" ); document.write( "---
\n" ); document.write( "Since sin(x) = 12/13, cos(x)=5/13
\n" ); document.write( "Since cos(y) = 3/5, sin(y) = 4/5
\n" ); document.write( "----
\n" ); document.write( "Therefore:
\n" ); document.write( "cos(x-y) = (5/13)(3/5)+(12/13)(4/5) = (63/65)
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\n" ); document.write( "2.) if the tangent of an angle is negative and its secant is positive, in which quadrant does the angle terminate
\n" ); document.write( "---
\n" ); document.write( "tangent is negative in the 2nd and 4th quadrants
\n" ); document.write( "secant is positive in the 1st and 4th quadrants.
\n" ); document.write( "Therefore the angle is in the 4th quadrant.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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