document.write( "Question 32036: m + 3 divided by m - 3 < or equal to 2, D = {Reals} \n" ); document.write( "
Algebra.Com's Answer #18602 by ikdeep(226)![]() ![]() You can put this solution on YOUR website! m + 3 divided by m - 3 < or equal to 2, D = {Reals}\r \n" ); document.write( "\n" ); document.write( "It can be written as \r \n" ); document.write( "\n" ); document.write( "(m + 3)/ m - 3 <= 2\r \n" ); document.write( "\n" ); document.write( "multiply both sides by m-3 and we get\r \n" ); document.write( "\n" ); document.write( "m + 3 <= 2m - 6\r \n" ); document.write( "\n" ); document.write( "put together like variables and we get\r \n" ); document.write( "\n" ); document.write( "0 <= 2m - m -6 - 3 \r \n" ); document.write( "\n" ); document.write( " 0 <= m - 9\r \n" ); document.write( "\n" ); document.write( "since D = real \r \n" ); document.write( "\n" ); document.write( "therefore m-9 >= 0\r \n" ); document.write( "\n" ); document.write( "subtract 9 from both sides,,we get \n" ); document.write( " \n" ); document.write( "m >= 9 \r \n" ); document.write( "\n" ); document.write( "hope this will help you \r \n" ); document.write( "\n" ); document.write( "Please feel free to revert back for any further queries. \n" ); document.write( " \n" ); document.write( " |