document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253677>Question 253677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with a very difficult math assignment i have recieved my math teachers makes it way more complicated then it has to be.\r<BR>\n" );
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document.write( "1.) if sin x= (12/13), cos y=(3/5) and x and y are acute angles, the value of cos(x-y) is <BR>\n" );
document.write( "a.(21/65) b.(63-65) c. -(14/65) d. -(33/65)\r<BR>\n" );
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document.write( "2.) if the tangent of an angle is negative and its secant is positive, in which quadrant does the angle terminate<BR>\n" );
document.write( "1,2,3 or 4 i thought it was the second quadrant but i dont understand the term terminate i wasnt sure if that ment the opposite of what it was.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #186016 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=186016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's take these one at at time:<BR>\n" );
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document.write( "1.) if sin x= (12/13), cos y=(3/5) and x and y are acute angles, the value of cos(x-y) is<BR>\n" );
document.write( "a.(21/65) b.(63/65) c. -(14/65) d. -(33/65)<BR>\n" );
document.write( "We have two angles, x and y.<BR>\n" );
document.write( "Sin(x) = 12/13.<BR>\n" );
document.write( "using Pythagorean theorem, we can find <BR>\n" );
document.write( "cos(x) = 5/13.<BR>\n" );
document.write( "Now,<BR>\n" );
document.write( "Cos(y) = 3/5<BR>\n" );
document.write( "using Pythagorean theorem, we can find <BR>\n" );
document.write( "sin(x) = 4/5.<BR>\n" );
document.write( "Cos(x-y) has formula<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28x-y%29+=+cos%28x%29%2Acos%28y%29+%2B+sin%28x%29%2Asin%28y%29 ALIGN=MIDDLE  ALT=\"cos%28x-y%29+=+cos%28x%29%2Acos%28y%29+%2B+sin%28x%29%2Asin%28y%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "when putting in our numbers, we get<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28x-y%29+=+%285%2F13%29%2A%283%2F5%29+%2B+%2812%2F13%29%2A%284%2F5%29 ALIGN=MIDDLE  ALT=\"cos%28x-y%29+=+%285%2F13%29%2A%283%2F5%29+%2B+%2812%2F13%29%2A%284%2F5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "which can be expressed as<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28x-y%29+=+15%2F%2865%29+%2B+48%2F65 ALIGN=MIDDLE  ALT=\"cos%28x-y%29+=+15%2F%2865%29+%2B+48%2F65\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28x-y%29+=+63%2F%2865%29 ALIGN=MIDDLE  ALT=\"cos%28x-y%29+=+63%2F%2865%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "which is [B]<BR>\n" );
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document.write( "2.) if the tangent of an angle is negative and its secant is positive, in which quadrant does the angle terminate\r<BR>\n" );
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document.write( "The tangent of x is negative in quadrant II and IV<BR>\n" );
document.write( "The secant (1 /cos) of x is positive in I and IV.<BR>\n" );
document.write( "They overlap in IV.<BR>\n" );
document.write( "Terminate is just a fancy word for where the vertex of the triangle sits. </SPAN>\n" );
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