document.write( "Question 253592: How do you factor the following system of equations?
\n" ); document.write( "3x-y=-2
\n" ); document.write( "x^3-y=0
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Algebra.Com's Answer #185984 by richwmiller(17219)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "No factoring here, yet!
\n" ); document.write( "Solve each for y and then set them equal to each other
\n" ); document.write( "3x-y=-2
\n" ); document.write( "3x+2=y
\n" ); document.write( "x^3-y=0
\n" ); document.write( "x^3=y
\n" ); document.write( "x^3=3x+2
\n" ); document.write( "x^3-3x-2=0
\n" ); document.write( "Now we factor
\n" ); document.write( "(x-2)(x+1)^2 = 0
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