document.write( "Question 253592: How do you factor the following system of equations?
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document.write( "3x-y=-2
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document.write( "x^3-y=0 \n" );
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Algebra.Com's Answer #185984 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! Reminder: \n" ); document.write( "You are limited to one problem per submission. \n" ); document.write( "No more than 4 submissions daily \n" ); document.write( "No similar problems.\r \n" ); document.write( "\n" ); document.write( "No factoring here, yet! \n" ); document.write( "Solve each for y and then set them equal to each other \n" ); document.write( "3x-y=-2 \n" ); document.write( "3x+2=y \n" ); document.write( "x^3-y=0 \n" ); document.write( "x^3=y \n" ); document.write( "x^3=3x+2 \n" ); document.write( "x^3-3x-2=0 \n" ); document.write( "Now we factor \n" ); document.write( "(x-2)(x+1)^2 = 0 \n" ); document.write( " \n" ); document.write( " |