document.write( "Question 31950This question is from textbook College Algebra
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document.write( ": sqrt(x+4) = x^2-5 I squared both sides and eventually came out with x^4-10x^2-x+25. I got as far as x(x^3-10x-1) + 21 but I think I'm off base.\r
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document.write( "Thank you so very much for all your help in this madness! \n" );
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Algebra.Com's Answer #18596 by stanbon(75887) ![]() You can put this solution on YOUR website! sqrt(x+4)=x^2-5 \n" ); document.write( "Square both sides to get: \n" ); document.write( "x+4=x^4-10x^2+25 \n" ); document.write( "x^4-10x^2-x+21=0 \n" ); document.write( "Graphing this with a TI-83 \n" ); document.write( "I get the following zeroes \n" ); document.write( "x=2.7566944... \n" ); document.write( "x=1.6214327... \n" ); document.write( "x=-1.882801... \n" ); document.write( "x=-2.495326... \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |