document.write( "Question 32066: I am given 2, 3-dimensional rectangles. The dimensions on A are l=4, w=10, h=18. The dimensions on b are l=8, w=20, h=36. I have to find the perimeters and explain the relationship between changes in dimensions and perimeter of the base of rectanular solids. Using ratios in the explanation.
\n" ); document.write( "I've done P=2(lw) so for Rectangle A the perimeter = 80 and rectangle B the perimeter = 320. I see that all of the dimensions of A are 1/2 the dimensions of B and that the perimeter of of B is 4 times that of A. But how do I explain all of this using ratios?
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Algebra.Com's Answer #18595 by venugopalramana(3286)\"\" \"About 
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\n" ); document.write( "I am given 2, 3-dimensional rectangles.
\n" ); document.write( "THEY ARE CALLED CUBOIDS OR RECTANGULAR PARALLELOPIPEDS
\n" ); document.write( " The dimensions on A are l=4, w=10, h=18. The dimensions on b are l=8, w=20, h=36. I have to find the perimeters and explain the relationship between changes in dimensions and perimeter of the base of rectanular solids. Using ratios in the explanation.
\n" ); document.write( "I've done P=2(lw)
\n" ); document.write( "NO PERIMETER IS 2(L+W)FOR ANY SIDE.
\n" ); document.write( "so for Rectangle A the perimeter = 80
\n" ); document.write( "NO...THIS =2(4+10)=28
\n" ); document.write( " and rectangle B the perimeter = 320.
\n" ); document.write( "NO..THIS =2(8+20)=56
\n" ); document.write( " I see that all of the dimensions of A are 1/2 the dimensions of B and that the perimeter of of B is 4 times that of A.
\n" ); document.write( "NO PERIMETER IS ALSO 1/2 TIMES.
\n" ); document.write( " But how do I explain all of this using ratios?
\n" ); document.write( "YOU CONCLUDE THAT PERIMETER CHANGES IN SAME RATIO OR IN PROPORTION TO CHANGE IN RATIO OF LENGTH OF SIDES.
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