document.write( "Question 253526: The length of a rectangle is twice its width. If the perimeter of the rectangle is 30IN , find its area. \r
\n" ); document.write( "\n" ); document.write( "so far i know, l=2w 2w(w)=30 2w^2=30 w^2=15 i know i need to get rid of the square root
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Algebra.Com's Answer #185849 by blwinbbbles(106)\"\" \"About 
You can put this solution on YOUR website!
You are close but the perimeter of a rectangle is all the sides added together so you would have length + length + width + width = 30\r
\n" ); document.write( "\n" ); document.write( "you can use L for length and w for width\r
\n" ); document.write( "\n" ); document.write( "So the two equations you will have are:\r
\n" ); document.write( "\n" ); document.write( "L = 2W
\n" ); document.write( "L+L+W+W=30 or 2L + 2W = 30\r
\n" ); document.write( "\n" ); document.write( "use substitution:\r
\n" ); document.write( "\n" ); document.write( "2(2W) + 2W = 30
\n" ); document.write( "4W + 2W = 30
\n" ); document.write( "6W = 30 divide both sides by 6
\n" ); document.write( "W = 5\r
\n" ); document.write( "\n" ); document.write( "Sub back into L=2(w) so L = 2(5)
\n" ); document.write( "L = 10\r
\n" ); document.write( "\n" ); document.write( "Hope this helps
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