document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249558>Question 249558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2in  longer than its width. If the perimeter of the rectangle is  36in , find its area.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185804 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=W+2<BR>\n" );
document.write( "36=2L+2W<BR>\n" );
document.write( "36=2(W+2)+2W<BR>\n" );
document.write( "36=2W+4+2W<BR>\n" );
document.write( "32=4W<BR>\n" );
document.write( "8=W<BR>\n" );
document.write( "L=10<BR>\n" );
document.write( "check <BR>\n" );
document.write( "2w+2L=20+16=36<BR>\n" );
document.write( "ok\r<BR>\n" );
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