document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253468>Question 253468</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the slant height of a regular pyramid whose base is a hexagon with one side measuring 30 units and whose altitude is 10&#8730;3 units. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185778 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> With a regular hexagon the side is the same length as the distance from centre to vertex, in this case 30<BR>\n" );
document.write( "So by Pythagoras, the slant height is sqrt ( 30^2 + 10sqrt(3) ^2) <BR>\n" );
document.write( "= sqrt (900 + 300) =sqrt  1200 = 20 sqrt 3 = 34.64 </SPAN>\n" );
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