document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253474>Question 253474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right circular cone has an altitude of 20 cm and a base of radius 4 cm. Find the lateral surface area and the total surface area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185764 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lateral SA is pi x slant height x radius<BR>\n" );
document.write( "slant height is done with Pythagoras so sqrt (20^2 + 4^2) = sqrt (416) = 14.7<BR>\n" );
document.write( "So Lat SA = 184.7 sq cm\r<BR>\n" );
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document.write( "Base area is pi x radius^2 = 50.3 sq cm<BR>\n" );
document.write( "Add the two for the total<BR>\n" );
document.write( "234.96 sq cm. </SPAN>\n" );
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