document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32057>Question 32057</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Since there is no section for partial equations, I will put the question here.<BR>\n" );
document.write( "(x^2 -x -21)/(2x^3-x^2+8x-4)\r<BR>\n" );
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document.write( "Thank you,<BR>\n" );
document.write( "Alexus </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18575 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x^2 -x -21)/(2x^3-x^2+8x-4)<BR>\n" );
document.write( "=(x^2 -x -21)/(2x-1)(x^2+4)<BR>\n" );
document.write( "Let (x^2 -x -21)/(2x-1)(x^2+4) = A/(2x-1)+(Bx+C)/(x^2+4)<BR>\n" );
document.write( "So,<BR>\n" );
document.write( "x^2 -x -21 = A((x^2+4)+(Bx+C)(2x-1)..............(1)<BR>\n" );
document.write( "For x=1/2:<BR>\n" );
document.write( "1/4-1/2-21=A(1/4+4)<BR>\n" );
document.write( "=>(21-42-4)/84 = A(17/4)<BR>\n" );
document.write( "=>-25/21=17A<BR>\n" );
document.write( "=> A=-25/(21*17) = -25/357;<BR>\n" );
document.write( "For x=0<BR>\n" );
document.write( "-21=4A-C<BR>\n" );
document.write( "=>C=4A+21; substitute the value of A to get C<BR>\n" );
document.write( "For x=1<BR>\n" );
document.write( "-21=5A+B+C<BR>\n" );
document.write( "substitute the value of A and C to get B<BR>\n" );
document.write( "After you get A, B, and C, use equation (1) to express the given equation in Partial Factor Decomposition form\r<BR>\n" );
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document.write( " </SPAN>\n" );
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