document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253368>Question 253368</A>: <I><SPAN STYLE=\"word-break: break-all;\"> All logs are base 12\r<BR>\n" );
document.write( "\n" );
document.write( "Logx=.5log9+1/3log27\r<BR>\n" );
document.write( "\n" );
document.write( "I got 49.5, I'm just wondering if it's right. THANKS! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185714 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> All logs are base 12<BR>\n" );
document.write( "log(x)=.5log(9)+1/3log(27) <BR>\n" );
document.write( "log(x)=log(3)+log(3) [log(sqrt of 9) + log(cube root of 27)]<BR>\n" );
document.write( "log(x)=log(9) <BR>\n" );
document.write( "x=9 This answer is the same no matter what base is used and you don't have to convert any logs to get the answer!<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );