document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253371>Question 253371</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if i took away two years from my age and gave them to my sister she be twice my age well why don't i take just one more year off mine and put it on my sister. That makes her three times my age? what is the age of each person </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185709 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185709\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let m=my age & s=sister's age<BR>\n" );
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document.write( "2(m-2)=s+2<BR>\n" );
document.write( "3(m-3)=s+3<BR>\n" );
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document.write( "2m-4=s+2<BR>\n" );
document.write( "3m-9=s+3<BR>\n" );
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document.write( "2m-s=6<BR>\n" );
document.write( "3m-s=12<BR>\n" );
document.write( "---------------subtract<BR>\n" );
document.write( "-m = -6<BR>\n" );
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document.write( "m=6<BR>\n" );
document.write( "s=6<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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