document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253415>Question 253415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4. If the perimeter of a rectangle is 8&#8730;2 cm, what is the smallest possible value of the length of one of its diagonals in cm?\r<BR>\n" );
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document.write( "I've tried:<BR>\n" );
document.write( "let length be l, width be w, and diagonal be d<BR>\n" );
document.write( "let l be x, then w will be:<BR>\n" );
document.write( "(8&#8730;2-2x)/2 = 4&#8730;2-x\r<BR>\n" );
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document.write( "d^2=l^2+w^2<BR>\n" );
document.write( "      =x^2+(4&#8730;2-x)^2<BR>\n" );
document.write( "      =x^2+(32-8&#8730;2x-x^2)<BR>\n" );
document.write( "      =32-8&#8730;2x... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185686 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A square has the smallest possible diagonals.<BR>\n" );
document.write( "s=8sqrt(2)/4<BR>\n" );
document.write( "=2sqrt(2) One side of the square<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "2sqrt(2)^2 + 2sqrt(2)^2 = c^2<BR>\n" );
document.write( "8+8=16 <BR>\n" );
document.write( "c=4 cm<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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