document.write( "Question 253407: i have two questions that i really need help with, help would be very appreciated.\r
\n" ); document.write( "\n" ); document.write( "1. A parcel of land is in the shape of an isosceles triangle. the base had a length of 673 feet and the two equal legs meet an angle of 43 degrees. Find, to the nearest square foot, the area of the parcel of land.\r
\n" ); document.write( "\n" ); document.write( "i know that area equals one half base times height but i have no idea how to figure out the height i dont know if i should cut the triangle in half or what.\r
\n" ); document.write( "\n" ); document.write( "2. The triangle top of a table has two sides of 14 inches and 16 inches and the angle between the sides is 30 degrees. Find the area of the tabletop, in square inches.\r
\n" ); document.write( "\n" ); document.write( "i drew i diagram and have attepmted several ways but none of the answers makes sense should i use sohcahtoa i desperatley need help.
\n" ); document.write( "

Algebra.Com's Answer #185672 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
1. A parcel of land is in the shape of an isosceles triangle. the base had a length of 673 feet and the two equal legs meet an angle of 43 degrees. Find, to the nearest square foot, the area of the parcel of land.
\n" ); document.write( "The other 2 angles are 68.5º.
\n" ); document.write( "The tan(68.5) = h/(base/2)
\n" ); document.write( "h = tan(68.5)*b/2 = tan(68.5)*336.5
\n" ); document.write( "h =~854.255
\n" ); document.write( "Area = bh/2 = 143728.4 sq feet
\n" ); document.write( "--------------------------------
\n" ); document.write( "2. The triangle top of a table has two sides of 14 inches and 16 inches and the angle between the sides is 30 degrees. Find the area of the tabletop, in square inches.
\n" ); document.write( "Call the 16\" side the base.
\n" ); document.write( "h = 14*sin(30) = 7
\n" ); document.write( "Area = bh/2 = 16*7/2 = 56 sq in
\n" ); document.write( "
\n" ); document.write( "
\n" );