document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32058>Question 32058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 60 fluid ounces of a 15% muriatic acid solution is needed to kill algae in a pool.  If the technician has a 5% solution and a pure solution on hand, how many ounces of each must be combined to create a 15% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18564 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume x ounces of 5% solution is to be mixed.<BR>\n" );
document.write( "Total volume of the mix=60 ounces; so, 60-x ounces of pure (100%) solution is to be mixed to kill algae in the pool;<BR>\n" );
document.write( "Thus, 5% of x + 100% of (60-x) = 15% of 60<BR>\n" );
document.write( "=> .05x+(60-x)  = .15*60<BR>\n" );
document.write( "=>60-.95x=9<BR>\n" );
document.write( "=>.95x=60-9<BR>\n" );
document.write( "=>.95x=51<BR>\n" );
document.write( "=>x=51/.95=53.68<BR>\n" );
document.write( "So, about 54 ounces of 5% solution is to be mixed with 6 ounces of pure solution.  For this type of questions, usually the numbers do not come so odd.<BR>\n" );
document.write( " </SPAN>\n" );
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