document.write( "Question 253332: log(36)=a and log(125)=b. Find (1/12) in terms of a and b. \n" ); document.write( "
Algebra.Com's Answer #185631 by stanbon(75887)\"\" \"About 
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log(36)=a
\n" ); document.write( "10^a = 36
\n" ); document.write( "10^a = 6^2
\n" ); document.write( "10^(a/2) = 6
\n" ); document.write( "log(6) = a/2\r
\n" ); document.write( "\n" ); document.write( "-------------------
\n" ); document.write( "and log(125)=b.
\n" ); document.write( "10^b = 125
\n" ); document.write( "10^b = 5^3
\n" ); document.write( "10^(b/3) = 5
\n" ); document.write( "log(5) = b/3
\n" ); document.write( "
\n" ); document.write( "---------\r
\n" ); document.write( "\n" ); document.write( "Find (1/12) in terms of a and b.
\n" ); document.write( "1/12 = 5/60 = 5/(6*10)
\n" ); document.write( "--------
\n" ); document.write( "log(1/12) = log(5/(6*10)) = log(5)-log(6)-log(10)
\n" ); document.write( "= (b/3) - (a/2) - 1
\n" ); document.write( "================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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