document.write( "Question 32058: 60 fluid ounces of a 15% muriatic acid solution is needed to kill algae in a pool. If the technician has a 5% solution and a pure solution on hand, how many ounces of each must be combined to create a 15% solution? \n" ); document.write( "
Algebra.Com's Answer #18563 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Let amount of 5% solution be \"x\" \n" ); document.write( "Then amount of 100% solution is \"60-x\" \n" ); document.write( "Muriatic acid in 5% solution is 0.05x \n" ); document.write( "Muriatic acid in 100% solution is 1(60-x) \n" ); document.write( "EQUATION: \n" ); document.write( "Acid + Acid = 0.15(60)=9 ml \n" ); document.write( "0.05x+60-x=9 ml \n" ); document.write( "-0.95x=-51 \n" ); document.write( "x=53.68 ml(amount of 5% solution) \n" ); document.write( "60-x=6.32 ml (amount of 100% solution) \n" ); document.write( "Cheers, \n" ); document.write( "stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |