document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=253327>Question 253327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve 125^(9x-2)=150\r<BR>\n" );
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document.write( "Solve 1/16=64^(4x-3)\r<BR>\n" );
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document.write( "Solve log(x+9)-logx=3\r<BR>\n" );
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document.write( "Use a graphing calculator solve 5^4x=1720 by grpaing. Round to the nearest Hundreth if neccesary. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #185624 by </B><A HREF=/tutors/aboutme.mpl?userid=hokies><B>hokies(65)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hokies><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=hokies><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=185624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A. Use the power rule for logarithms:<BR>\n" );
document.write( "(9x-2)*log(125)=log(150)<BR>\n" );
document.write( "9x = log(150)/log(125)+2<BR>\n" );
document.write( "x = (log(150)/log(125)+2)/9\r<BR>\n" );
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document.write( "B. 1/16=64^(4x-3)<BR>\n" );
document.write( "4^(-2)=4^(3*(4x-3))<BR>\n" );
document.write( "-2 = 3*(4x-3)<BR>\n" );
document.write( "-2/3 = 4x-3<BR>\n" );
document.write( "4x = 3-2/3<BR>\n" );
document.write( "4x = 7/3<BR>\n" );
document.write( "x = 7/12\r<BR>\n" );
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document.write( "C. log(x+9)-log(x)=3<BR>\n" );
document.write( "Use the division rule for logarithms:<BR>\n" );
document.write( "log((x+9)/x)=3<BR>\n" );
document.write( "(x+9)/x = 10^3<BR>\n" );
document.write( "1+9/x = 10^3<BR>\n" );
document.write( "9/x = 999<BR>\n" );
document.write( "x = 9/999<BR>\n" );
document.write( "x = 1/111\r<BR>\n" );
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document.write( "D. x=1.16 </SPAN>\n" );
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