document.write( "Question 249758: Question: Find three consecutive odd integers such that twice the first added to three times the second is equal to 83. \n" ); document.write( "
Algebra.Com's Answer #185611 by richwmiller(17219)\"\" \"About 
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2n+1
\n" ); document.write( "2n+3
\n" ); document.write( "2n+5
\n" ); document.write( "2(2n+1)+3(2n+3)=83
\n" ); document.write( "This is rather curious since the third integer is not mentioned.\r
\n" ); document.write( "\n" ); document.write( "I tried this with n+1, n+3 and n+5
\n" ); document.write( "2(n+1)+3(n+3)=83
\n" ); document.write( "and there are no integer solutions.
\n" ); document.write( "Something is wrong or missing.
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