document.write( "Question 253299: Which statement must be true if a parabola represented by the equation y = ax^2 + bx + c does not intersect the x-axis?\r
\n" ); document.write( "\n" ); document.write( "b^2 – 4ac = 0
\n" ); document.write( "b^2 – 4ac < 0
\n" ); document.write( "b^2 – 4ac > 0, and b^2 – 4ac is a perfect square.
\n" ); document.write( "b^2 – 4ac > 0, and b^2 – 4ac is not a perfect square
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Algebra.Com's Answer #185587 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
b2 – 4ac < 0
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\n" ); document.write( "This is covered well by the on-site solver:
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B12x%2B40+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2812%29%5E2-4%2A1%2A40=-16\".
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\n" ); document.write( " The discriminant -16 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -16 is + or - \"sqrt%28+16%29+=+4\".
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\n" ); document.write( " The solution is \"x%5B12%5D+=+%28-12%2B-i%2Asqrt%28+-16+%29%29%2F2%5C1+=++%28-12%2B-i%2A4%29%2F2%5C1+\", or
\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B12%2Ax%2B40+%29\"

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