document.write( "Question 253285: The tens-digit of a three digit number is 3 less than 5 times the units digit. Three times the sum of the digits is 2 more than 4 times the hundreds digit. If the digits are reversed, the new number is 594 less than the original number. Find the original number. (find a system of 3 equations then use the system to find the original number). \n" ); document.write( "
Algebra.Com's Answer #185576 by JimboP1977(311)\"\" \"About 
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Let H be the hundreds digit
\n" ); document.write( "Let T be the tens digit
\n" ); document.write( "Let U be the units digit.\r
\n" ); document.write( "\n" ); document.write( "We are given the following:\r
\n" ); document.write( "\n" ); document.write( "\"T%2B3=5U\" (1)
\n" ); document.write( "\"3%28H%2BT%2BU%29-2=4H\" (2)
\n" ); document.write( "\"100U%2B10T%2BH=100H%2B10T%2BU-594\" (3)\r
\n" ); document.write( "\n" ); document.write( "Rearrange (1) to equal T. Then substitute into (2).\r
\n" ); document.write( "\n" ); document.write( "\"3%28H%2B%285U-3%29%2BU%29-2=4H\"
\n" ); document.write( "\"3%28H%2B6U-3%29-2=4H\"
\n" ); document.write( "\"3H%2B18U-9-2=4H\"
\n" ); document.write( "\"3H%2B18U-11=4H\"
\n" ); document.write( "\"18U-11=H\" (4)\r
\n" ); document.write( "\n" ); document.write( "Collect terms in (3) to give \"99U-99H=-594\" (5)\r
\n" ); document.write( "\n" ); document.write( "Subsitute (4) into (5) to give \"99U-99%2818U-11%29=-594\"
\n" ); document.write( "\"99U-1782U%2B1089=-594\"
\n" ); document.write( "\"-1683U%2B1089=-594\"
\n" ); document.write( "\"-1683U=-1683\"
\n" ); document.write( "\"U=1\"\r
\n" ); document.write( "\n" ); document.write( "Plug this result into (1) and (4) to give \"T=8\" and \"H=7\"\r
\n" ); document.write( "\n" ); document.write( "So the original number 781.\r
\n" ); document.write( "\n" ); document.write( "Does that make any sense?\r
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